Python 3 – downside changing keyboard enter to integer

I am having an issue utilizing the int() operate on a consumer enter from the keyboard in Python 3 (newest model from web site). The precise program will carry out varied numerical calculations, however I’ve written a brief check program that exhibits the issue. The int() operate works nice for values embedded within the code, however crashes if the identical quantity/format is entered by way of the keyboard.

1. dummy_num = (2.5) #simply an instance float quantity
2. dummy_num = int(dummy_num) #converts 2.5 to integer 2
3. print (f”{dummy_num}”) #verifies results of “2”
4. variable_test = enter (“sort 2.5 please:”)
5. print (f”{variable_test}”) #verifies 2.5 is definitely entered
6. variable_test = int(variable_test)

This system runs as anticipated for traces 1 to five. If 2.5 is entered by way of the keyboard in line 4, line 5 prints 2.5, however then line 6 crashes this system.
An error message is generated as follows:
variable_test = int(variable_test)
ValueError: invalid literal for int() with base 10: ‘2.5’

I do not perceive why the int() operate works nice for the worth “2.5” in line 2, however crashes in line 6 – though line 5 exhibits that the quantity entered is certainly 2.5 and the identical program instruction works nice in line 2.

Sorry if this can be a beginner error, however I’ve run out of concepts. Be aware that I put just a few #feedback within the above code only for the aim of this query.